浅谈asp无组件上传并插入到数据库里
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以下为引用的内容：<% Response.Buffer = True Server.ScriptTimeOut=9999999 On Error Resume Next %> <!--#include file="conn.asp"--> <!--#include file="function.asp"--> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=gb2312" /> <meta http-equiv="Content-Language" content="zh-cn" /> <meta content="all" name="robots" /> <style type="text/css"> <!-- body,input {font-size:12px;} --> </style> <title>ASP文件上传</title> </head> <body id="body"> <% checkuser() ExtName = "xls" '允许扩展名 SavePath = "upload" '保存路径 If Right(SavePath,1)<>"/" Then SavePath=SavePath&"/" '在目录后加(/) CheckAndCreateFolder(SavePath) UpLoadAll_a = Request.TotalBytes '取得客户端全部内容 If(UpLoadAll_a>0) Then Set UploadStream_c = Server.CreateObject("ADODB.Stream") UploadStream_c.Type = 1 UploadStream_c.Open UploadStream_c.Write Request.BinaryRead(UpLoadAll_a) UploadStream_c.Position = 0 FormDataAll_d = UploadStream_c.Read CrLf_e = chrB(13)&chrB(10) FormStart_f = InStrB(FormDataAll_d,CrLf_e) FormEnd_g = InStrB(FormStart_f 1,FormDataAll_d,CrLf_e) Set FormStream_h = Server.Createobject("ADODB.Stream") FormStream_h.Type = 1 FormStream_h.Open UploadStream_c.Position = FormStart_f 1 UploadStream_c.CopyTo FormStream_h,FormEnd_g-FormStart_f-3 FormStream_h.Position = 0 FormStream_h.Type = 2 FormStream_h.CharSet = "GB2312" FormStreamText_i = FormStream_h.Readtext FormStream_h.Close FileName_j = Mid(FormStreamText_i,InstrRev(FormStreamText_i,"") 1,FormEnd_g) If(CheckFileExt(FileName_j,ExtName)) Then SaveFile = Server.MapPath(SavePath & FileName_j) If Err Then Response.Write "文件上传： <span style=""color:red;"">文件上传出错!</span> <a href=""" & Request.ServerVariables("URL") &""">重新上传文件</a><br />" Err.Clear Else SaveFile = CheckFileExists(SaveFile) SaveFileName = Mid(SaveFile,InstrRev(SaveFile,"") 1) session("file")=SaveFileName k=Instrb(FormDataAll_d,CrLf_e&CrLf_e) 4 l=Instrb(k 1,FormDataAll_d,leftB(FormDataAll_d,FormStart_f-1))-k-2 FormStream_h.Type=1 FormStream_h.Open UploadStream_c.Position=k-1 UploadStream_c.CopyTo FormStream_h,l FormStream_h.SaveToFile SaveFile,2 SaveFileName = Mid(SaveFile,InstrRev(SaveFile,"") 1) Dim Conn1,Driver1,DBPath1,Rs1,Sql1 ' 建立Connection对象 Set Conn1 = Server.CreateObject("ADODB.Connection") Driver1 = "Driver={Microsoft Excel Driver (*.xls)};" DBPath1 = "DBQ=" & Server.MapPath("upload/"&SaveFileName) '调用Open 方法打开数据库 Conn1.Open Driver1 & DBPath1 Sql1="Select * From [Sheet1$] " Set Rs1=Conn1.Execute(Sql1) IF Rs1.Eof And Rs1.Bof Then Response.write "没有找到您需要的数据!!" Else Do While Not Rs1.EOF '插入到数据库中 OpenDataBase "select * from abc" if len(rs1(0))=7 then ctime=left(rs1(0),4) else ctime=left(rs1(0),5) end if rs.addnew rs("time")=ctime rs.update CloseDataBase() Rs1.MoveNext Loop End IF Rs1.Close Set Rs1=nothing Conn1.Close Set Conn1=Nothing '插入到数据库中结束 Response.write "文件上传： <span style=""color:red;"">" & SaveFileName & " </span>文件上传成功!<a href='choise.asp''>继续上传文件</a><br />" End If Else Response.write "文件上传： <span style=""color:red;"">文件格式不正确!</span> <a href=""" & Request.ServerVariables("URL") &""">重新上传文件</a><br />" End If Else %> <script language="Javascript"> <!-- function ValidInput() { if(document.upform.upfile.value=="") { alert("请选择上传文件！") document.upform.upfile.focus() return false } return true } // --> </script> <form action='<%= Request.ServerVariables("URL") %>' method='post' name="upform" onsubmit="return ValidInput()" enctype="multipart/form-data"> 文件上传： <input type='file' name='upfile' size="40"> <input type='submit' value="上传"> </form> <% End if Set FormStream_h = Nothing UploadStream.Close Set UploadStream = Nothing %> </body> </html> （编辑：银川站长网） 【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容! |
